What is the derivative of 1/((x+2)) ?

The derivative of 1/((x+2)) is -1/((x+2)^2)

What is the first derivative of 1/((x+2)) ?

The first derivative of 1/((x+2)) is -1/((x+2)^2)

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\frac{d}{d x} (\frac{1}{( x + 2 )})

- \frac{1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{( x + 2 )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

= - \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= - \frac{1}{( x + 2 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 2 ) ^{2}}

\int \frac{x ^{3}}{e ^{3 x^{4}}} d x

e^{x}, at x = 3

\int_{0}^{1} x^{3} 1 - x^{2} d x

- \frac{2}{3 x ^{2}}

\frac{\partial}{\partial x} (2 x y - 3 y^{2})

What is the derivative of 1/((x+2)) ?
The derivative of 1/((x+2)) is -1/((x+2)^2)
What is the first derivative of 1/((x+2)) ?
The first derivative of 1/((x+2)) is -1/((x+2)^2)