What is the tangent of e^x,\at x=3 ?

The tangent of e^x,\at x=3 is y=e^3x-2e^3

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tangent of e^x,\at x=3

tangent of

e^{x}, at x = 3

y = e^{3} x - 2 e^{3}

Solution steps

Find the tangent point:

(3, e^{3})

Find the slope of

y = e^{x} : \frac{d y}{d x} = e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = e^{3}

Find the line with slope m=

e^{3}

and passing through

(3, e^{3}) : y = e^{3} x - 2 e^{3}

y = e^{3} x - 2 e^{3}

\int_{0}^{1} x^{3} 1 - x^{2} d x

- \frac{2}{3 x ^{2}}

\frac{\partial}{\partial x} (2 x y - 3 y^{2})

\frac{d}{d x} ((x^{3} + 3) 2^{- 7 x})

\frac{d}{d x} (24 x^{2} + 8 x - 5)