What is the derivative of f(x)=(3x)/(1-x) ?

The derivative of f(x)=(3x)/(1-x) is 3/((1-x)^2)

What is the first derivative of f(x)=(3x)/(1-x) ?

The first derivative of f(x)=(3x)/(1-x) is 3/((1-x)^2)

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derivative of

f (x) = \frac{3 x}{1 - x}

\frac{3}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x}{1 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{1 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} ( 1 - x ) - \frac{d}{d x} ( 1 - x ) x}{( 1 - x ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (1 - x) = - 1

= 3 \cdot \frac{1 \cdot ( 1 - x ) - ( - 1 ) x}{( 1 - x ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot ( 1 - x ) - ( - 1 ) x}{( 1 - x ) ^{2}} : \frac{3}{( 1 - x ) ^{2}}

= \frac{3}{( 1 - x ) ^{2}}

x \to 0 lim (\frac{7}{x})

- \frac{n ( - 1 ) ^{n}}{n + 1}

\int sin^{2} (x) \cdot cos^{2} (x) d x

f (x) = \frac{1}{x ^{6}}, (2, \frac{1}{64})

y = x^{3} - 2 x + 2

What is the derivative of f(x)=(3x)/(1-x) ?
The derivative of f(x)=(3x)/(1-x) is 3/((1-x)^2)
What is the first derivative of f(x)=(3x)/(1-x) ?
The first derivative of f(x)=(3x)/(1-x) is 3/((1-x)^2)