What is the derivative of-(n(-1)^n)/(n+1) ?

The derivative of-(n(-1)^n)/(n+1) is Undefined

What is the first derivative of-(n(-1)^n)/(n+1) ?

The first derivative of-(n(-1)^n)/(n+1) is Undefined

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derivative of

- \frac{n ( - 1 ) ^{n}}{n + 1}

Undefined

Solution steps

\frac{d}{d n} (- \frac{n ( - 1 ) ^{n}}{n + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d n} (\frac{n ( - 1 ) ^{n}}{n + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - \frac{\frac{d}{d n} ( n ( - 1 ) ^{n} ) ( n + 1 ) - \frac{d}{d n} ( n + 1 ) n ( - 1 ) ^{n}}{( n + 1 ) ^{2}}

\frac{d}{d n} (n (- 1)^{n}) =

Undefined

= Undefined

\int sin^{2} (x) \cdot cos^{2} (x) d x

f (x) = \frac{1}{x ^{6}}, (2, \frac{1}{64})

y = x^{3} - 2 x + 2

\int x^{4} + cos (3 x) d x

\frac{\partial}{\partial x} (ln (5 x^{2} y^{2}))

What is the derivative of-(n(-1)^n)/(n+1) ?
The derivative of-(n(-1)^n)/(n+1) is Undefined
What is the first derivative of-(n(-1)^n)/(n+1) ?
The first derivative of-(n(-1)^n)/(n+1) is Undefined