What is (\partial)/(\partial x)(ln(5x^2y^2)) ?

The answer to (\partial)/(\partial x)(ln(5x^2y^2)) is 2/x

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(\partial)/(\partial x)(ln(5x^2y^2))

\frac{\partial}{\partial x} (ln (5 x^{2} y^{2}))

\frac{2}{x}

Solution steps

\frac{\partial}{\partial x} (ln (5 x^{2} y^{2}))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{5 x ^{2} y ^{2}} \frac{\partial}{\partial x} (5 x^{2} y^{2})

= \frac{1}{5 x ^{2} y ^{2}} \frac{\partial}{\partial x} (5 x^{2} y^{2})

\frac{\partial}{\partial x} (5 x^{2} y^{2}) = 10 y^{2} x

= \frac{1}{5 x ^{2} y ^{2}} \cdot 10 y^{2} x

Simplify

\frac{1}{5 x ^{2} y ^{2}} \cdot 10 y^{2} x : \frac{2}{x}

= \frac{2}{x}

\frac{d}{d x} (\frac{e ^{x^{3}}}{sin ( 2 x )})

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 x}

y = x, y = 3 x, x + y = 4

n = 1 \sum \infty 0.9 9^{n}

\int sin (x + 2) d x

What is (\partial)/(\partial x)(ln(5x^2y^2)) ?
The answer to (\partial)/(\partial x)(ln(5x^2y^2)) is 2/x