en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(t)=(2t)/(1+t^2)

Solution

f (t) = \frac{2 t}{1 + t ^{2}}

Solution

Domain : - \infty < t < \infty

Range : - 1 \leq f (t) \leq 1

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- 1, - 1), Maximum (1, 1)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 1, 1]

Solution steps

Domain of

\frac{2 t}{1 + t ^{2}} : - \infty < t < \infty

Range of

\frac{2 t}{1 + t ^{2}} : - 1 \leq f (t) \leq 1

Axis interception points of

\frac{2 t}{1 + t ^{2}} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{2 t}{1 + t ^{2}} :

Horizontal

: y = 0

Extreme Points of

\frac{2 t}{1 + t ^{2}} :

Minimum

(- 1, - 1),

Maximum

(1, 1)

Graph

Popular Examples

derivative of f(x)=10x^4 derivative of

f (x) = 10 x^{4}

derivative of 9x^4y^8-2x^my^5-x^9y^n

\frac{d}{d x} (9 x^{4} y^{8} - 2 x^{m} y^{5} - x^{9} y^{n})

integral from 0 to 1 of e^{x^5}

\int_{0}^{1} e^{x^{5}} d x

sum from n=5 to infinity of (7^n)/(10^n)

n = 5 \sum \infty \frac{7 ^{n}}{1 0 ^{n}}

y^'-y=4te^{2t},y(0)=1

y^{^{'}} - y = 4 t e^{2 t}, y (0) = 1

Frequently Asked Questions (FAQ)

What is the f(t)=(2t)/(1+t^2) ?
The f(t)=(2t)/(1+t^2) is