What is the tangent of 3x^2-4x+6 ?

The tangent of 3x^2-4x+6 is y=(6a_{0}-4)x-3a_{0}^2+6

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tangent of 3x^2-4x+6

tangent of

3 x^{2} - 4 x + 6

y = (6 a_{0} - 4) x - 3 a_{0}^{2} + 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} - 4 a_{0} + 6)

Find the slope of

y = 3 x^{2} - 4 x + 6 : \frac{d y}{d x} = 6 x - 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 a_{0} - 4

Find the line with slope m=

6 a_{0} - 4

and passing through

(a_{0}, 3 a_{0}^{2} - 4 a_{0} + 6) : y = (6 a_{0} - 4) x - 3 a_{0}^{2} + 6

y = (6 a_{0} - 4) x - 3 a_{0}^{2} + 6

x \to - \infty lim (- 2 e^{x})

\frac{\partial}{\partial y} (\frac{x - y}{x y + 2})

f (5) = 4 x^{2} + 3 x - \frac{8}{x ^{2}}

n = 1 \sum \infty \frac{n}{n ^{2} + 1} x^{n}

y = x^{2} - 2, (- 2, 2)

What is the tangent of 3x^2-4x+6 ?
The tangent of 3x^2-4x+6 is y=(6a_{0}-4)x-3a_{0}^2+6