What is (\partial)/(\partial x)(-3ycos(3x)) ?

The answer to (\partial)/(\partial x)(-3ycos(3x)) is 9ysin(3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-3ycos(3x))

\frac{\partial}{\partial x} (- 3 y cos (3 x))

9 y sin (3 x)

Solution steps

\frac{\partial}{\partial x} (- 3 y cos (3 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 y \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= - 3 y (- sin (3 x) \cdot 3)

Simplify

= 9 y sin (3 x)

(x y^{2} - 3 y) d x + (x^{2} y - 3 x) d y = 0

\int \frac{1 - x}{3 e ^{x}} d x

x \to 3 lim (x^{2} - 4)

x \to 0 lim (\frac{( 1 + x ) ^{3} - 1}{x})

\frac{d}{d x} (sin (\frac{π}{x}))

What is (\partial)/(\partial x)(-3ycos(3x)) ?
The answer to (\partial)/(\partial x)(-3ycos(3x)) is 9ysin(3x)