What is the derivative of 2x^2-x ?

The derivative of 2x^2-x is 4x-1

What is the first derivative of 2x^2-x ?

The first derivative of 2x^2-x is 4x-1

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derivative of

2 x^{2} - x

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 4 x - 1

\int \frac{7 x ^{2} - 6 x + 8}{x ^{3} + 4 x} d x

\frac{d}{d x} (x sin (x y))

t \to \infty lim (cos (t))

\frac{d y}{d t} = \frac{3 y}{t} + t^{5}

x \to c lim (f (x))