What is the tangent of 2/(x-6) ?

The tangent of 2/(x-6) is y=-2/((a_{0)-6)^2}x+(4a_{0}-12)/((a_{0)-6)^2}

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tangent of 2/(x-6)

tangent of

\frac{2}{x - 6}

y = - \frac{2}{( a _{0} - 6 ) ^{2}} x + \frac{4 a _{0} - 12}{( a _{0} - 6 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0} - 6})

Find the slope of

y = \frac{2}{x - 6} : \frac{d y}{d x} = - \frac{2}{( x - 6 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{( a _{0} - 6 ) ^{2}}

Find the line with slope m=

- \frac{2}{( a _{0} - 6 ) ^{2}}

and passing through

(a_{0}, \frac{2}{a _{0} - 6}) : y = - \frac{2}{( a _{0} - 6 ) ^{2}} x + \frac{4 a _{0} - 12}{( a _{0} - 6 ) ^{2}}

y = - \frac{2}{( a _{0} - 6 ) ^{2}} x + \frac{4 a _{0} - 12}{( a _{0} - 6 ) ^{2}}

y^{^{'}} - 2 x y = x y^{2}

\int 12 sin (x) d x

n \to \infty lim (\frac{1}{2 n})

\int \frac{x ^{2}}{2 x + 1} d x

\frac{d}{d x} (5 x cos (\frac{x}{5}))

What is the tangent of 2/(x-6) ?
The tangent of 2/(x-6) is y=-2/((a_{0)-6)^2}x+(4a_{0}-12)/((a_{0)-6)^2}