What is the solution for (dy)/(dx)=-(1+y^2)/(1+x^2) ?

The solution for (dy)/(dx)=-(1+y^2)/(1+x^2) is y=tan(-arctan(x)+c_{1})

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(dy)/(dx)=-(1+y^2)/(1+x^2)

\frac{d y}{d x} = - \frac{1 + y ^{2}}{1 + x ^{2}}

y = tan (- arctan (x) + c_{1})

Solution steps

\frac{d y}{d x} = - \frac{1 + y ^{2}}{1 + x ^{2}}

Solve separable ODE:

y = tan (- arctan (x) + c_{1})

y = tan (- arctan (x) + c_{1})

\frac{d}{d t} (1 - 2 cos (t))

\int \frac{8 x + 9}{( x ^{2} + 9 ) ( 8 - x )} d x

\int \frac{1}{6 y} d y

\int \frac{1}{49 + t ^{2}} d t

y = sin (x), at x = \frac{7 π}{6}

What is the solution for (dy)/(dx)=-(1+y^2)/(1+x^2) ?
The solution for (dy)/(dx)=-(1+y^2)/(1+x^2) is y=tan(-arctan(x)+c_{1})