What is the solution for (dy)/(dt)-2y=3e^{-2t} ?

The solution for (dy)/(dt)-2y=3e^{-2t} is y=-3/(4e^{2t)}+c_{1}e^{2t}

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(dy)/(dt)-2y=3e^{-2t}

\frac{d y}{d t} - 2 y = 3 e^{- 2 t}

y = - \frac{3}{4 e ^{2 t}} + c_{1} e^{2 t}

Solution steps

\frac{d y}{d t} - 2 y = 3 e^{- 2 t}

Solve linear ODE:

y = - \frac{3}{4 e ^{2 t}} + c_{1} e^{2 t}

y = - \frac{3}{4 e ^{2 t}} + c_{1} e^{2 t}

\frac{d}{d x} y = (3 x + 2) (5 x^{2} + 4)

\int \frac{x}{x - 1 + 1} d x

f (x) = 2 e^{- x} x - e^{- x} x^{2}

\frac{x ^{2}}{x + 5}

1 - 2 x^{2}, ∣ x ∣

What is the solution for (dy)/(dt)-2y=3e^{-2t} ?
The solution for (dy)/(dt)-2y=3e^{-2t} is y=-3/(4e^{2t)}+c_{1}e^{2t}