What is the solution for derivative of y=(3x+2)(5x^2+4) ?

The solution for derivative of y=(3x+2)(5x^2+4) is y=(15x^4)/4+6x^2+(10x^3)/3+8x+c_{1}

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derivative of y=(3x+2)(5x^2+4)

\frac{d}{d x} y = (3 x + 2) (5 x^{2} + 4)

y = \frac{15 x ^{4}}{4} + 6 x^{2} + \frac{10 x ^{3}}{3} + 8 x + c_{1}

Solution steps

\frac{d y}{d x} = (3 x + 2) (5 x^{2} + 4)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (3 x + 2) (5 x^{2} + 4) d x

\int (3 x + 2) (5 x^{2} + 4) d x = \frac{15 x ^{4}}{4} + 6 x^{2} + \frac{10 x ^{3}}{3} + 8 x + c_{1}

y = \frac{15 x ^{4}}{4} + 6 x^{2} + \frac{10 x ^{3}}{3} + 8 x + c_{1}

\int \frac{x}{x - 1 + 1} d x

f (x) = 2 e^{- x} x - e^{- x} x^{2}

\frac{x ^{2}}{x + 5}

1 - 2 x^{2}, ∣ x ∣

\frac{1}{1 - x}, 7

What is the solution for derivative of y=(3x+2)(5x^2+4) ?
The solution for derivative of y=(3x+2)(5x^2+4) is y=(15x^4)/4+6x^2+(10x^3)/3+8x+c_{1}