What is the derivative of 9x^2+y^2 ?

The derivative of 9x^2+y^2 is 18x+2y(dy)/(dx)

What is the first derivative of 9x^2+y^2 ?

The first derivative of 9x^2+y^2 is 18x+2y(dy)/(dx)

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\frac{d}{d x} (9 x^{2} + y^{2})

18 x + 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (9 x^{2} + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (y^{2})

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 18 x + 2 y \frac{d y}{d x}

y = 5 x^{2}, (4, 80)

x \to - \infty lim (- ln (x))

\frac{d}{d x} (\frac{x}{x ^{2} + 1})

f^{^{'}} (x) = - 2 ln (x) + x^{2} - 4 + e^{x} + x^{e}

f (x) = x^{2} - 6 x + 8, g (x) = - 2 x + 8

What is the derivative of 9x^2+y^2 ?
The derivative of 9x^2+y^2 is 18x+2y(dy)/(dx)
What is the first derivative of 9x^2+y^2 ?
The first derivative of 9x^2+y^2 is 18x+2y(dy)/(dx)