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Popular >

y^{''}+8y^'+16=0

Solution

y^{^{''}} + 8 y^{^{'}} + 16 = 0

Solution

y = c_{1} + c_{2} e^{- 8 t} - 2 t

Solution steps

y^{''} (t) + 8 y^{'} (t) + 16 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 8 t} - 2 t

y = c_{1} + c_{2} e^{- 8 t} - 2 t

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}+8y^'+16=0 ?
The solution for y^{''}+8y^'+16=0 is y=c_{1}+c_{2}e^{-8t}-2t