What is the solution for (dy)/(dt)=y(1-0.0002y) ?

The solution for (dy)/(dt)=y(1-0.0002y) is y=-(e^{t+c_{1}})/(1-0.0002e^{t+c_{1)}}

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(dy)/(dt)=y(1-0.0002y)

\frac{d y}{d t} = y (1 - 0.0002 y)

y = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

Solution steps

\frac{d y}{d t} = y (1 - 0.0002 y)

Solve separable ODE:

y = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

y = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

\int 2^{x} x d x

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (π) = 0, y^{^{'}} (π) = 2

f (x) = 3 x^{2}, at x = 4

\frac{d}{d x} (\frac{x + 5}{x})

x^{2} y^{^{''}} + x y^{^{'}} - y = x^{\frac{1}{2}}

What is the solution for (dy)/(dt)=y(1-0.0002y) ?
The solution for (dy)/(dt)=y(1-0.0002y) is y=-(e^{t+c_{1}})/(1-0.0002e^{t+c_{1)}}