What is the tangent of y= 5/(x^3) ?

The tangent of y= 5/(x^3) is y=-(15)/(a_{0)^4}x+(20)/(a_{0)^3}

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tangent of y= 5/(x^3)

tangent of

y = \frac{5}{x ^{3}}

y = - \frac{15}{a _{0}^{4}} x + \frac{20}{a _{0}^{3}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{5}{a _{0}^{3}})

Find the slope of

y = \frac{5}{x ^{3}} : \frac{d y}{d x} = - \frac{15}{x ^{4}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{15}{a _{0}^{4}}

Find the line with slope m=

- \frac{15}{a _{0}^{4}}

and passing through

(a_{0}, \frac{5}{a _{0}^{3}}) : y = - \frac{15}{a _{0}^{4}} x + \frac{20}{a _{0}^{3}}

y = - \frac{15}{a _{0}^{4}} x + \frac{20}{a _{0}^{3}}

\frac{d}{d x} ((3 x)^{4 x})

\frac{d}{d x} (c x^{- 7})

\frac{d y}{d x} = \frac{sec ( y )}{( x + 2 ) ^{2}}

\int \frac{k}{x ^{4}} d x

\frac{\partial}{\partial y} (2 x - 4 y)

What is the tangent of y= 5/(x^3) ?
The tangent of y= 5/(x^3) is y=-(15)/(a_{0)^4}x+(20)/(a_{0)^3}