What is the tangent of f(x)=2x^2+3x-2,\at a=-1 ?

The tangent of f(x)=2x^2+3x-2,\at a=-1 is y=(4a+3)x-2a^2-2

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tangent of f(x)=2x^2+3x-2,\at a=-1

tangent of

f (x) = 2 x^{2} + 3 x - 2, at a = - 1

y = (4 a + 3) x - 2 a^{2} - 2

Solution steps

Compute the tangent line to the general point

x = a

Find the tangent point:

(a, 2 a^{2} + 3 a - 2)

Find the slope of

f (x) = 2 x^{2} + 3 x - 2 : \frac{df ( x )}{d x} = 4 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a + 3

Find the line with slope m=

4 a + 3

and passing through

(a, 2 a^{2} + 3 a - 2) : y = (4 a + 3) x - 2 a^{2} - 2

y = (4 a + 3) x - 2 a^{2} - 2

\int_{5}^{5.89} 0.75 (y - 5)^{2} + 5 d y

\frac{d}{d x} (- x e^{- 2 x y})

0.01 (0.2 t^{2} + 4 t + 64)^{\frac{2}{3}}

x \to 2 lim (3 x + 1)

\int \frac{x - 1}{2 x - x + 1} d x

What is the tangent of f(x)=2x^2+3x-2,\at a=-1 ?
The tangent of f(x)=2x^2+3x-2,\at a=-1 is y=(4a+3)x-2a^2-2