What is the sum from n=5 to infinity of (5^n)/(6^n) ?

The sum from n=5 to infinity of (5^n)/(6^n) is converges

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sum from n=5 to infinity of (5^n)/(6^n)

n = 5 \sum \infty \frac{5 ^{n}}{6 ^{n}}

converges

Solution steps

n = 5 \sum \infty \frac{5 ^{n}}{6 ^{n}}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (\frac{5}{4 x ^{3} + 4})

\int 28 (7 x - 2)^{- 5} d x

\frac{\partial}{\partial x} (\frac{( 2 x - 2 y )}{4 x + 2 y})

\frac{\partial}{\partial x} (t^{2} e^{\frac{x ^{2}}{2 t}})

- x, - 10 x + 14, x = 0

What is the sum from n=5 to infinity of (5^n)/(6^n) ?
The sum from n=5 to infinity of (5^n)/(6^n) is converges