What is the solution for (dy)/(dx)= y/(x^2),y(1)=2 ?

The solution for (dy)/(dx)= y/(x^2),y(1)=2 is y=2e^{-1/x+1}

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(dy)/(dx)= y/(x^2),y(1)=2

\frac{d y}{d x} = \frac{y}{x ^{2}}, y (1) = 2

y = 2 e^{- \frac{1}{x} + 1}

Solution steps

\frac{d y}{d x} = \frac{y}{x ^{2}}

Solve separable ODE:

y = 2 e^{- \frac{1}{x} + 1}

y = 2 e^{- \frac{1}{x} + 1}

arctan (sin (2 x))

f (x) = x, at x = \frac{1}{81}

5 \frac{1}{x}

\int_{0}^{3.5} 90 x d x

n = 1 \sum \infty \frac{1}{2 n ^{2}}

What is the solution for (dy)/(dx)= y/(x^2),y(1)=2 ?
The solution for (dy)/(dx)= y/(x^2),y(1)=2 is y=2e^{-1/x+1}