What is the limit as x approaches 2 of x/([(x^2)-4]) ?

The limit as x approaches 2 of x/([(x^2)-4]) is diverges

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limit as x approaches 2 of x/([(x^2)-4])

x \to 2 lim (\frac{x}{[ ( x ^{2} ) - 4 ]})

diverges

Solution steps

x \to 2 lim (\frac{x}{[ x ^{2} - 4 ]})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{x}{[ x ^{2} - 4 ]}) = \infty

x \to 2 - lim (\frac{x}{[ x ^{2} - 4 ]}) = - \infty

= diverges

(x + \frac{2}{y}) d y + y d x = 0

\int_{0}^{2} \frac{1}{x ^{3}} d x

\frac{\partial}{\partial x} (- 2 y + 2 x)

f (x) = (ln (x))^{2}, at x = 11

\int_{0}^{2} x^{2} - x d x

What is the limit as x approaches 2 of x/([(x^2)-4]) ?
The limit as x approaches 2 of x/([(x^2)-4]) is diverges