What is the solution for (dy)/(dt)-2y=y^4 ?

The solution for (dy)/(dt)-2y=y^4 is y=\sqrt[3]{2/(e^{-6t-c_{1)}-1}}

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(dy)/(dt)-2y=y^4

\frac{d y}{d t} - 2 y = y^{4}

y = 3 \frac{2}{e ^{- 6 t - c_{1}} - 1}

Solution steps

\frac{d y}{d t} - 2 y = y^{4}

Solve Bernoulli ODE:

y = 3 \frac{2}{e ^{- 6 t - c_{1}} - 1}

y = 3 \frac{2}{e ^{- 6 t - c_{1}} - 1}

\frac{d}{d x} ((x - 3) (x^{2} + 6))

\frac{d}{d x} (\frac{ln ( 9 x )}{9 x})

\frac{d}{d x} (\frac{a}{x} + b x)

(17 - 13) (178)

\frac{\partial}{\partial x} (\frac{x}{cos ( y )})

What is the solution for (dy)/(dt)-2y=y^4 ?
The solution for (dy)/(dt)-2y=y^4 is y=\sqrt[3]{2/(e^{-6t-c_{1)}-1}}