What is the derivative of a/x+bx ?

The derivative of a/x+bx is -a/(x^2)+b

What is the first derivative of a/x+bx ?

The first derivative of a/x+bx is -a/(x^2)+b

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\frac{d}{d x} (\frac{a}{x} + b x)

- \frac{a}{x ^{2}} + b

Solution steps

\frac{d}{d x} (\frac{a}{x} + b x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{a}{x}) + \frac{d}{d x} (b x)

\frac{d}{d x} (\frac{a}{x}) = - \frac{a}{x ^{2}}

\frac{d}{d x} (b x) = b

= - \frac{a}{x ^{2}} + b

(17 - 13) (178)

\frac{\partial}{\partial x} (\frac{x}{cos ( y )})

y^{^{'}} = x^{2} - 6 x + 14

\frac{d y}{d x} + 3 y = 4

y^{^{'}} = \frac{x + 1}{y}

What is the derivative of a/x+bx ?
The derivative of a/x+bx is -a/(x^2)+b
What is the first derivative of a/x+bx ?
The first derivative of a/x+bx is -a/(x^2)+b