What is the solution for (dy)/(dx)+2xy^4=0 ?

The solution for (dy)/(dx)+2xy^4=0 is y=-1/(\sqrt[3]{3(-x^2+c_{1))}}

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(dy)/(dx)+2xy^4=0

\frac{d y}{d x} + 2 x y^{4} = 0

y = - \frac{1}{3 3 ( - x ^{2} + c _{1} )}

Solution steps

\frac{d y}{d x} + 2 x y^{4} = 0

Solve separable ODE:

y = - \frac{1}{3 3 ( - x ^{2} + c _{1} )}

y = - \frac{1}{3 3 ( - x ^{2} + c _{1} )}

\frac{d}{d x} (\frac{1}{6 + x})

(1 + x^{2}) d y + (1 + y^{2}) d x = 0

\int (ln (x) - ln (x y)) d x

x \to \infty lim (i x)

\frac{d}{d x} (4 x^{3} - 5 x^{2} + 4 x - 1)

What is the solution for (dy)/(dx)+2xy^4=0 ?
The solution for (dy)/(dx)+2xy^4=0 is y=-1/(\sqrt[3]{3(-x^2+c_{1))}}