What is the integral of 3cos(t) ?

The integral of 3cos(t) is 3sin(t)+C

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integral of 3cos(t)

\int 3 cos (t) d t

3 sin (t) + C

Solution steps

\int 3 cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= 3 sin (t)

Add a constant to the solution

= 3 sin (t) + C

x \to 3 π + lim (1 + csc (x))

(5^{x})^{^{'}}

\frac{\partial}{\partial x} (14 x^{3} cos (7 x^{2} y))

f (x) = 4, g (x) = \frac{e ^{x}}{5}, x = 0

(y - y x^{2}) (\frac{d y}{d x}) = (y + 1)^{2}