What is the derivative of arcsec(6x) ?

The derivative of arcsec(6x) is 1/(sqrt(x^2)\sqrt{36x^2-1)}

What is the first derivative of arcsec(6x) ?

The first derivative of arcsec(6x) is 1/(sqrt(x^2)\sqrt{36x^2-1)}

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derivative of

arcsec (6 x)

\frac{1}{x ^{2} 36 x ^{2} - 1}

Solution steps

\frac{d}{d x} (arcsec (6 x))

Apply the chain rule:

\frac{1}{( 6 x ) ^{2} ( 6 x ) ^{2} - 1} \frac{d}{d x} (6 x)

= \frac{1}{( 6 x ) ^{2} ( 6 x ) ^{2} - 1} \frac{d}{d x} (6 x)

\frac{d}{d x} (6 x) = 6

= \frac{1}{( 6 x ) ^{2} ( 6 x ) ^{2} - 1} \cdot 6

Simplify

\frac{1}{( 6 x ) ^{2} ( 6 x ) ^{2} - 1} \cdot 6 : \frac{1}{x ^{2} 36 x ^{2} - 1}

= \frac{1}{x ^{2} 36 x ^{2} - 1}

\frac{\partial}{\partial x} (e^{x} g)

36 y^{^{''}} - 36 y^{^{'}} - 7 y = 0

x \to a lim (f (x))

\int e^{- t} sin (t) d t

\int (3 x^{2} + x - 2) d x

What is the derivative of arcsec(6x) ?
The derivative of arcsec(6x) is 1/(sqrt(x^2)\sqrt{36x^2-1)}
What is the first derivative of arcsec(6x) ?
The first derivative of arcsec(6x) is 1/(sqrt(x^2)\sqrt{36x^2-1)}