What is the integral of (cos(x)+sec^2(x)) ?

The integral of (cos(x)+sec^2(x)) is sin(x)+tan(x)+C

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integral of (cos(x)+sec^2(x))

\int (cos (x) + sec^{2} (x)) d x

sin (x) + tan (x) + C

Solution steps

\int cos (x) + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (x) d x + \int sec^{2} (x) d x

\int cos (x) d x = sin (x)

\int sec^{2} (x) d x = tan (x)

= sin (x) + tan (x)

Add a constant to the solution

= sin (x) + tan (x) + C

\int_{0}^{3} (5 x - x^{2}) d x

\int x^{2} ln (e x) d x

y^{^{''}} - 4 y^{^{'}} + 4 y = t^{- 7} e^{2 t}

\int \frac{1}{( 1 - y ) ( 2 - y )} d y

f (s) = 2 t e^{- 5 t}

What is the integral of (cos(x)+sec^2(x)) ?
The integral of (cos(x)+sec^2(x)) is sin(x)+tan(x)+C