What is laplacetransform f(s)=2te^{-5t} ?

The answer to laplacetransform f(s)=2te^{-5t} is 2/((s+5)^2)

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laplacetransform f(s)=2te^{-5t}

laplace transform

f (s) = 2 t e^{- 5 t}

\frac{2}{( s + 5 ) ^{2}}

Solution steps

L {2 e^{- 5 t} t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {t e^{- 5 t}}

L {t e^{- 5 t}} : \frac{1}{( s + 5 ) ^{2}}

= 2 \cdot \frac{1}{( s + 5 ) ^{2}}

Refine

2 \frac{1}{( s + 5 ) ^{2}} : \frac{2}{( s + 5 ) ^{2}}

= \frac{2}{( s + 5 ) ^{2}}

f (x) = x^{2} + 2 x, [1, 2]

\frac{d}{d x} (- 2 x^{2} + 2 x)

x \to 1 - lim (1 - e^{\frac{1}{x - 1}})

\int \frac{1}{17 - x ^{2}} d x

x e^{x}

What is laplacetransform f(s)=2te^{-5t} ?
The answer to laplacetransform f(s)=2te^{-5t} is 2/((s+5)^2)