en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-4 to 4 of 16-x^2

Solution

\int_{- 4}^{4} 16 - x^{2} d x

Solution

\frac{256}{3}

+1

Decimal Notation

85.33333 \dots

Solution steps

\int_{- 4}^{4} 16 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{4} 16 d x - \int_{- 4}^{4} x^{2} d x

\int_{- 4}^{4} 16 d x = 128

\int_{- 4}^{4} x^{2} d x = \frac{128}{3}

= 128 - \frac{128}{3}

Simplify

128 - \frac{128}{3} : \frac{256}{3}

= \frac{256}{3}

Popular Examples

(dy)/(dx)=5sqrt(y)

\frac{d y}{d x} = 5 y

21xy^'-ln(x^7)=0

21 x y^{^{'}} - ln (x^{7}) = 0

integral of (2x)/((x^2+5)ln(x^2+5))

\int \frac{2 x}{( x ^{2} + 5 ) ln ( x ^{2} + 5 )} d x

tangent of f(x)=9x^2-x^3,\at x=1 tangent of

f (x) = 9 x^{2} - x^{3}, at x = 1

(\partial)/(\partial y)(3x+2y)

\frac{\partial}{\partial y} (3 x + 2 y)

Frequently Asked Questions (FAQ)

What is the integral from-4 to 4 of 16-x^2 ?
The integral from-4 to 4 of 16-x^2 is 256/3