en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

21xy^'-ln(x^7)=0

Solution

21 x y^{^{'}} - ln (x^{7}) = 0

Solution

y = \frac{1}{6} ln^{2} (x) + c_{1}

Solution steps

21 x y^{'} (x) - ln (x^{7}) = 0

Isolate

y^{'} (x) : y^{'} (x) = \frac{ln ( x )}{3 x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{ln ( x )}{3 x} d x

\int \frac{ln ( x )}{3 x} d x = \frac{1}{6} ln^{2} (x) + c_{1}

y = \frac{1}{6} ln^{2} (x) + c_{1}

Popular Examples

integral of (2x)/((x^2+5)ln(x^2+5))

\int \frac{2 x}{( x ^{2} + 5 ) ln ( x ^{2} + 5 )} d x

tangent of f(x)=9x^2-x^3,\at x=1 tangent of

f (x) = 9 x^{2} - x^{3}, at x = 1

(\partial)/(\partial y)(3x+2y)

\frac{\partial}{\partial y} (3 x + 2 y)

(dy)/(dx)=e^{3x+y}

\frac{d y}{d x} = e^{3 x + y}

sum from k=1 to infinity of 0.5^kT

k = 1 \sum \infty 0. 5^{k} T

Frequently Asked Questions (FAQ)

What is the solution for 21xy^'-ln(x^7)=0 ?
The solution for 21xy^'-ln(x^7)=0 is y= 1/6 ln^2(x)+c_{1}