What is the integral from 0 to 1 of x^23x^2 ?

The integral from 0 to 1 of x^23x^2 is 3/5

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integral from 0 to 1 of x^23x^2

\int_{0}^{1} x^{2} 3 x^{2} d x

\frac{3}{5}

Decimal Notation

0.6

Solution steps

\int_{0}^{1} x^{2} \cdot 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} x^{2} x^{2} d x

Simplify

x^{2} x^{2} : x^{4}

= 3 \cdot \int_{0}^{1} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{1}

= 3 [\frac{x ^{5}}{5}]_{0}^{1}

Compute the boundaries:

\frac{1}{5}

= 3 \cdot \frac{1}{5}

Simplify

= \frac{3}{5}

\frac{d}{d x} (ln (7 x^{2} + 3 y^{2}))

\frac{d}{d x} (\frac{x + 1}{x ^{5}})

\frac{\partial}{\partial y} (4 x^{2} y - 5 x y^{2})

y = 9 - 0.25 x^{2}, y = 0, [2, 5]

\frac{1}{3 x + 1}

What is the integral from 0 to 1 of x^23x^2 ?
The integral from 0 to 1 of x^23x^2 is 3/5