What is the derivative of arctan(-2x) ?

The derivative of arctan(-2x) is -2/(4x^2+1)

What is the first derivative of arctan(-2x) ?

The first derivative of arctan(-2x) is -2/(4x^2+1)

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derivative of

arctan (- 2 x)

- \frac{2}{4 x ^{2} + 1}

Solution steps

\frac{d}{d x} (arctan (- 2 x))

Apply the chain rule:

\frac{1}{( - 2 x ) ^{2} + 1} \frac{d}{d x} (- 2 x)

= \frac{1}{( - 2 x ) ^{2} + 1} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= \frac{1}{( - 2 x ) ^{2} + 1} (- 2)

Simplify

\frac{1}{( - 2 x ) ^{2} + 1} (- 2) : - \frac{2}{4 x ^{2} + 1}

= - \frac{2}{4 x ^{2} + 1}

y^{^{''}} + b y^{^{'}} = 0

x^{2}, x^{2} - 4 x + 4, 0, 2

\int 2 - \frac{1}{x} d x

\frac{\partial}{\partial x} (2 cos (x y^{2}))

\frac{( 4 x ^{2} + 8 x + 6 )}{x}

What is the derivative of arctan(-2x) ?
The derivative of arctan(-2x) is -2/(4x^2+1)
What is the first derivative of arctan(-2x) ?
The first derivative of arctan(-2x) is -2/(4x^2+1)