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Popular >

area x^2,x^2-4x+4,0,2

Solution

area

x^{2}, x^{2} - 4 x + 4, 0, 2

Solution

4

Solution steps

Apply the area formula:

\int_{0}^{2} x^{2} - (x^{2} - 4 x + 4) d x

Solve

\int_{0}^{2} x^{2} - (x^{2} - 4 x + 4) d x : 4

The area is:

= 4

Popular Examples

integral of 2-1/x

\int 2 - \frac{1}{x} d x

(\partial)/(\partial x)(2cos(xy^2))

\frac{\partial}{\partial x} (2 cos (x y^{2}))

derivative of ((4x^2+8x+6))/(sqrt(x))derivative of

\frac{( 4 x ^{2} + 8 x + 6 )}{x}

limit as x approaches 0 of |x-4|

x \to 0 lim (∣ x - 4 ∣)

integral from-3 to 1 of (x^2-4x)

\int_{- 3}^{1} (x^{2} - 4 x) d x

Frequently Asked Questions (FAQ)

What is area x^2,x^2-4x+4,0,2 ?
The answer to area x^2,x^2-4x+4,0,2 is 4