What is the d/(dt)(sin(2pit)) ?

The d/(dt)(sin(2pit)) is cos(2pit)*2pi

What is the first d/(dt)(sin(2pit)) ?

The first d/(dt)(sin(2pit)) is cos(2pit)*2pi

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\frac{d}{d t} (sin (2 π t))

cos (2 π t) \cdot 2 π

Solution steps

\frac{d}{d t} (sin (2 π t))

Apply the chain rule:

cos (2 π t) \frac{d}{d t} (2 π t)

= cos (2 π t) \frac{d}{d t} (2 π t)

\frac{d}{d t} (2 π t) = 2 π

= cos (2 π t) \cdot 2 π

y = x^{4} + 8 x^{2} - x, (1, 8)

\int x + 2 - \frac{1}{x + 1} d x

\int \frac{x + 1}{x ^{2} + 2 x} d x

n = 1 \sum \infty \frac{1}{3} (\frac{e}{2})^{n}

\int \frac{x ^{5} + 2 x ^{3} - 3 x}{( x ^{2} + 1 ) ^{3}} d x

What is the d/(dt)(sin(2pit)) ?
The d/(dt)(sin(2pit)) is cos(2pit)*2pi
What is the first d/(dt)(sin(2pit)) ?
The first d/(dt)(sin(2pit)) is cos(2pit)*2pi