What is the derivative of e^{2x^x} ?

The derivative of e^{2x^x} is e^{2x^x}*2x^x(ln(x)+1)

What is the first derivative of e^{2x^x} ?

The first derivative of e^{2x^x} is e^{2x^x}*2x^x(ln(x)+1)

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derivative of

e^{2 x^{x}}

e^{2 x^{x}} \cdot 2 x^{x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (e^{2 x^{x}})

Apply the chain rule:

e^{2 x^{x}} \frac{d}{d x} (2 x^{x})

= e^{2 x^{x}} \frac{d}{d x} (2 x^{x})

\frac{d}{d x} (2 x^{x}) = 2 x^{x} (ln (x) + 1)

= e^{2 x^{x}} \cdot 2 x^{x} (ln (x) + 1)

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What is the derivative of e^{2x^x} ?
The derivative of e^{2x^x} is e^{2x^x}*2x^x(ln(x)+1)
What is the first derivative of e^{2x^x} ?
The first derivative of e^{2x^x} is e^{2x^x}*2x^x(ln(x)+1)