What is area 1/(4(1+x^2)), 1/8 x^2 ?

The answer to area 1/(4(1+x^2)), 1/8 x^2 is pi/8-1/12

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area 1/(4(1+x^2)), 1/8 x^2

area

\frac{1}{4 ( 1 + x ^{2} )}, \frac{1}{8} x^{2}

\frac{π}{8} - \frac{1}{12}

Decimal Notation

0.30936 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{1}{4 ( 1 + x ^{2} )} - \frac{1}{8} x^{2} d x

Solve

\int_{- 1}^{1} \frac{1}{4 ( 1 + x ^{2} )} - \frac{1}{8} x^{2} d x : \frac{π}{8} - \frac{1}{12}

The area is:

= \frac{π}{8} - \frac{1}{12}

n = 0 \sum \infty e^{- 8 n}

(1 - x)^{3} - lo g_{e} (1 - x)

\frac{5 x ^{2}}{3 x - 1}

\int_{1}^{2} 3 - \frac{6}{x ^{2}} d x

\int \frac{6 cosh ( x )}{x} d x

What is area 1/(4(1+x^2)), 1/8 x^2 ?
The answer to area 1/(4(1+x^2)), 1/8 x^2 is pi/8-1/12