What is the integral from-2 to 3 of 4/(x^4) ?

The integral from-2 to 3 of 4/(x^4) is diverges

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integral from-2 to 3 of 4/(x^4)

\int_{- 2}^{3} \frac{4}{x ^{4}} d x

diverges

Solution steps

\int_{- 2}^{3} \frac{4}{x ^{4}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{4}{x ^{4}} d x + \int_{0}^{3} \frac{4}{x ^{4}} d x

\int_{- 2}^{0} \frac{4}{x ^{4}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{d}{d x} (\frac{1}{x ^{2} - x})

\int - 2 e^{x^{2}} sin (2 y) + \frac{x ^{2}}{2} + 1

4 + x^{2} + 4 x^{4}, 3

\int \frac{7 e ^{3 t}}{1 + e ^{6 t}} d t

2 x^{2} + 3, - 1, 2

What is the integral from-2 to 3 of 4/(x^4) ?
The integral from-2 to 3 of 4/(x^4) is diverges