What is taylor 4+x^2+4x^4,3 ?

The answer to taylor 4+x^2+4x^4,3 is 337+438(x-3)+217(x-3)^2+48(x-3)^3+4(x-3)^4

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taylor 4+x^2+4x^4,3

taylor

4 + x^{2} + 4 x^{4}, 3

337 + 438 (x - 3) + 217 (x - 3)^{2} + 48 (x - 3)^{3} + 4 (x - 3)^{4}

Solution steps

Apply the Taylor Formula

= 337 + \frac{\frac{d}{d x} ( 4 + x ^{2} + 4 x ^{4} ) ( 3 )}{1 !} (x - 3) + \frac{\frac{d ^{2}}{d x ^{2}} ( 4 + x ^{2} + 4 x ^{4} ) ( 3 )}{2 !} (x - 3)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 4 + x ^{2} + 4 x ^{4} ) ( 3 )}{3 !} (x - 3)^{3} + \dots

Evaluate Derivatives

= 337 + \frac{438}{1 !} (x - 3) + \frac{434}{2 !} (x - 3)^{2} + \frac{288}{3 !} (x - 3)^{3} + \frac{96}{4 !} (x - 3)^{4}

Refine

= 337 + 438 (x - 3) + 217 (x - 3)^{2} + 48 (x - 3)^{3} + 4 (x - 3)^{4}

\int \frac{7 e ^{3 t}}{1 + e ^{6 t}} d t

2 x^{2} + 3, - 1, 2

\int \frac{x}{x ^{2} + 36} d x

\frac{d}{d x} (e^{- k x^{2}})

\int_{1}^{\infty} \frac{1}{3 x - 2} d x

What is taylor 4+x^2+4x^4,3 ?
The answer to taylor 4+x^2+4x^4,3 is 337+438(x-3)+217(x-3)^2+48(x-3)^3+4(x-3)^4