What is the integral from 1 to infinity of 1/(3x-2) ?

The integral from 1 to infinity of 1/(3x-2) is diverges

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integral from 1 to infinity of 1/(3x-2)

\int_{1}^{\infty} \frac{1}{3 x - 2} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{3 x - 2} d x

Compute the indefinite integral:

\int \frac{1}{3 x - 2} d x = \frac{1}{3} ln ∣ 3 x - 2 ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{3 x - 2} d x =

diverges

= diverges

\int \frac{2 x + 1}{x ^{2} + 5 x + 6} d x

\frac{d}{d x} (2 x^{2} + 5)

\int 4 x^{2} e^{3 x} d x

y^{^{''}} + y = 3 e^{- 4 x}

\int \frac{3 ln ^{2} ( x )}{x ^{2}} d x

What is the integral from 1 to infinity of 1/(3x-2) ?
The integral from 1 to infinity of 1/(3x-2) is diverges