What is the derivative of ((x+3^2)/((x+2)^5(x+4)^7)) ?

The derivative of ((x+3^2)/((x+2)^5(x+4)^7)) is (2(x+3)(-5x^2-29x-43))/((x+2)^6(x+4)^8)

What is the first derivative of ((x+3^2)/((x+2)^5(x+4)^7)) ?

The first derivative of ((x+3^2)/((x+2)^5(x+4)^7)) is (2(x+3)(-5x^2-29x-43))/((x+2)^6(x+4)^8)

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\frac{d}{d x} (\frac{( x + 3 ) ^{2}}{( x + 2 ) ^{5} ( x + 4 ) ^{7}})

\frac{2 ( x + 3 ) ( - 5 x ^{2} - 29 x - 43 )}{( x + 2 ) ^{6} ( x + 4 ) ^{8}}

Solution steps

\frac{d}{d x} (\frac{( x + 3 ) ^{2}}{( x + 2 ) ^{5} ( x + 4 ) ^{7}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( ( x + 3 ) ^{2} ) ( x + 2 ) ^{5} ( x + 4 ) ^{7} - \frac{d}{d x} ( ( x + 2 ) ^{5} ( x + 4 ) ^{7} ) ( x + 3 ) ^{2}}{( ( x + 2 ) ^{5} ( x + 4 ) ^{7} ) ^{2}}

\frac{d}{d x} ((x + 3)^{2}) = 2 (x + 3)

\frac{d}{d x} ((x + 2)^{5} (x + 4)^{7}) = 5 (x + 2)^{4} (x + 4)^{7} + 7 (x + 4)^{6} (x + 2)^{5}

= \frac{2 ( x + 3 ) ( x + 2 ) ^{5} ( x + 4 ) ^{7} - ( 5 ( x + 2 ) ^{4} ( x + 4 ) ^{7} + 7 ( x + 4 ) ^{6} ( x + 2 ) ^{5} ) ( x + 3 ) ^{2}}{( ( x + 2 ) ^{5} ( x + 4 ) ^{7} ) ^{2}}

Simplify

\frac{2 ( x + 3 ) ( x + 2 ) ^{5} ( x + 4 ) ^{7} - ( 5 ( x + 2 ) ^{4} ( x + 4 ) ^{7} + 7 ( x + 4 ) ^{6} ( x + 2 ) ^{5} ) ( x + 3 ) ^{2}}{( ( x + 2 ) ^{5} ( x + 4 ) ^{7} ) ^{2}} : \frac{2 ( x + 3 ) ( - 5 x ^{2} - 29 x - 43 )}{( x + 2 ) ^{6} ( x + 4 ) ^{8}}

= \frac{2 ( x + 3 ) ( - 5 x ^{2} - 29 x - 43 )}{( x + 2 ) ^{6} ( x + 4 ) ^{8}}

\int co tan^{2} (x) d x

\frac{\partial}{\partial x} (\frac{1}{2 - x + y})

2 x + x^{2} - 5, at x = 1

y = \frac{x}{4 + x ^{2}}, (0, 0)

\int \frac{x ^{2} - 8}{x ^{4}} d x

What is the derivative of ((x+3^2)/((x+2)^5(x+4)^7)) ?
The derivative of ((x+3^2)/((x+2)^5(x+4)^7)) is (2(x+3)(-5x^2-29x-43))/((x+2)^6(x+4)^8)
What is the first derivative of ((x+3^2)/((x+2)^5(x+4)^7)) ?
The first derivative of ((x+3^2)/((x+2)^5(x+4)^7)) is (2(x+3)(-5x^2-29x-43))/((x+2)^6(x+4)^8)