What is the solution for (x+2y)dy=dx ?

The solution for (x+2y)dy=dx is y=-\W(-1/(2e^{(x+c_{1))/2}})-1-x/2

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(x+2y)dy=dx

(x + 2 y) d y = d x

y = - W (- \frac{1}{2 e ^{\frac{x + c _{1}}{2}}}) - 1 - \frac{x}{2}

Solution steps

(x + 2 y) d y = d x

Solve using substitution:

y = - W (- \frac{1}{2 e ^{\frac{x + c _{1}}{2}}}) - 1 - \frac{x}{2}

y = - W (- \frac{1}{2 e ^{\frac{x + c _{1}}{2}}}) - 1 - \frac{x}{2}

\frac{d}{d x} (x \cdot e^{\frac{1}{x}})

x \to 1 lim (x (1))

\int_{4}^{8} \frac{2}{x ^{3}} d x

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\int \frac{7}{7 x ^{2} + 14 x + 5} d x

What is the solution for (x+2y)dy=dx ?
The solution for (x+2y)dy=dx is y=-\W(-1/(2e^{(x+c_{1))/2}})-1-x/2