What is the tangent of f(x)=x^3+x,\at x=0 ?

The tangent of f(x)=x^3+x,\at x=0 is y=x

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tangent of f(x)=x^3+x,\at x=0

tangent of

f (x) = x^{3} + x, at x = 0

y = x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = x^{3} + x : \frac{df ( x )}{d x} = 3 x^{2} + 1

Compute the slope of

f (x) = x^{3} + x

x = 0 : m = 1

Find the line with slope m=

1

and passing through

(0, 0) : y = x

y = x

cos^{2} (a x)

f^{^{'}} (s) = 10 s - 12 s^{3}, f (3) = 2

n = 0 \sum \infty x^{2 n}

y = x^{2} + 1, (2, 5)

\frac{d}{d t} (e^{7 t})

What is the tangent of f(x)=x^3+x,\at x=0 ?
The tangent of f(x)=x^3+x,\at x=0 is y=x