What is the tangent of f(x)=x^2+2x,\at x=34 ?

The tangent of f(x)=x^2+2x,\at x=34 is y=70x-1156

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tangent of f(x)=x^2+2x,\at x=34

tangent of

f (x) = x^{2} + 2 x, at x = 34

y = 70 x - 1156

Solution steps

Find the tangent point:

(34, 1224)

Find the slope of

f (x) = x^{2} + 2 x : \frac{df ( x )}{d x} = 2 x + 2

Compute the slope of

f (x) = x^{2} + 2 x

x = 34 : m = 70

Find the line with slope m=

70

and passing through

(34, 1224) : y = 70 x - 1156

y = 70 x - 1156

x \to \infty lim (2^{x})

\int \frac{x ^{2} + 2 x - 1}{( x + 1 ) ( x + 2 ) ( x + 3 )} d x

f (x) = (4 x - 9)^{2}

y^{^{'}} - y = x, y (0) = 1

x \to - 2 lim (x^{3} + 8)

What is the tangent of f(x)=x^2+2x,\at x=34 ?
The tangent of f(x)=x^2+2x,\at x=34 is y=70x-1156