What is the tangent of f(x)= 1/(1+x^2),(1, 1/2) ?

The tangent of f(x)= 1/(1+x^2),(1, 1/2) is y=-1/2 x+1

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tangent of f(x)= 1/(1+x^2),(1, 1/2)

tangent of

f (x) = \frac{1}{1 + x ^{2}}, (1, \frac{1}{2})

y = - \frac{1}{2} x + 1

Solution steps

Find the slope of

f (x) = \frac{1}{1 + x ^{2}} : \frac{df ( x )}{d x} = - \frac{2 x}{( 1 + x ^{2} ) ^{2}}

Compute the slope of

f (x) = \frac{1}{1 + x ^{2}}

(1, \frac{1}{2}) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(1, \frac{1}{2}) : y = - \frac{1}{2} x + 1

y = - \frac{1}{2} x + 1

\frac{d}{d y} (4)

\int 15 z^{3} e^{z} d z

e^{- 4 (t - 1)}

y^{^{'''}} + 4 y^{^{'}} = cot (2 x)

f (x) = x^{2}, (0, - 4)

What is the tangent of f(x)= 1/(1+x^2),(1, 1/2) ?
The tangent of f(x)= 1/(1+x^2),(1, 1/2) is y=-1/2 x+1