What is the tangent of f(x)=x^2,(0,-4) ?

The tangent of f(x)=x^2,(0,-4) is y=4x-4 \lor y=-4x-4

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tangent of f(x)=x^2,(0,-4)

tangent of

f (x) = x^{2}, (0, - 4)

y = 4 x - 4 or y = - 4 x - 4

Solution steps

Slope of the tangent line at

(0, - 4) : m = \frac{x ^{2} + 4}{x}

Find the slope of

f (x) = x^{2} : m = 2 x

Solve

2 x = \frac{x ^{2} + 4}{x} : x = 2, x = - 2

Find the tangent line at

x = 2 : y = 4 x - 4

Find the tangent line at

x = - 2 : y = - 4 x - 4

y = 4 x - 4 or y = - 4 x - 4

3 x^{3} + \frac{4}{x}

\frac{\partial}{\partial x} (x ln (y) - y^{2} 2^{x y})

y^{^{''}} + 9 y = - sin (3 x)

\int_{0}^{1} \frac{1}{x ^{2} - 2 x + 2} d x

\frac{\partial}{\partial φ} (ρ sin (φ) sin (θ))

What is the tangent of f(x)=x^2,(0,-4) ?
The tangent of f(x)=x^2,(0,-4) is y=4x-4 \lor y=-4x-4