What is the solution for x^3+y^2sqrt(x^4+2)y^'=0 ?

The solution for x^3+y^2sqrt(x^4+2)y^'=0 is y=\sqrt[3]{-3/2 sqrt(x^4+2)+c_{1}}

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x^3+y^2sqrt(x^4+2)y^'=0

x^{3} + y^{2} x^{4} + 2 y^{^{'}} = 0

Solution steps

x^{3} + y^{2} x^{4} + 2 y^{'} (x) = 0

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What is the solution for x^3+y^2sqrt(x^4+2)y^'=0 ?
The solution for x^3+y^2sqrt(x^4+2)y^'=0 is y=\sqrt[3]{-3/2 sqrt(x^4+2)+c_{1}}