What is the derivative of 3x+2/x ?

The derivative of 3x+2/x is 3-2/(x^2)

What is the first derivative of 3x+2/x ?

The first derivative of 3x+2/x is 3-2/(x^2)

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\frac{d}{d x} (3 x + \frac{2}{x})

3 - \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x + \frac{2}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (\frac{2}{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= 3 - \frac{2}{x ^{2}}

\frac{\partial}{\partial x} (sin (- 3 x) cos (4 y))

\frac{d}{d x} (x^{3} - 6 x^{2} + 11 x - 6)

\int 1 - y^{2} d y

\int \frac{1}{f ( f - u )} df

What is the derivative of 3x+2/x ?
The derivative of 3x+2/x is 3-2/(x^2)
What is the first derivative of 3x+2/x ?
The first derivative of 3x+2/x is 3-2/(x^2)