What is area 5cos(2x),5-5cos(2x) ?

The answer to area 5cos(2x),5-5cos(2x) is 5sqrt(3)+(10pi)/3

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area 5cos(2x),5-5cos(2x)

area

5 cos (2 x), 5 - 5 cos (2 x)

53 + \frac{10 π}{3}

Decimal Notation

19.13222 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{6}}^{\frac{5 π}{6}} ∣ 5 cos (2 x) - (5 - 5 cos (2 x)) ∣ d x

Solve

\int_{\frac{π}{6}}^{\frac{5 π}{6}} ∣ 5 cos (2 x) - (5 - 5 cos (2 x)) ∣ d x : 53 + \frac{10 π}{3}

The area is:

= 53 + \frac{10 π}{3}

\int \frac{- 1}{( x + 1 ) ^{2}} d x

\frac{\partial}{\partial x} (e^{- 8 x^{2} - 5 y^{2}})

n = 0 \sum \infty - \frac{1}{n + 1}

\int e^{3 x} (sin (3 x) + cos (3 x)) d x

What is area 5cos(2x),5-5cos(2x) ?
The answer to area 5cos(2x),5-5cos(2x) is 5sqrt(3)+(10pi)/3