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Popular >

derivative of \sqrt[5]{t}+2sqrt(t^5)

Solution

derivative of

Solution

\frac{1 + 25 t ^{\frac{23}{10}}}{5 t ^{\frac{4}{5}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (2 t^{5}) = 5 t^{\frac{3}{2}}

= \frac{1}{5 t ^{\frac{4}{5}}} + 5 t^{\frac{3}{2}}

Simplify

\frac{1}{5 t ^{\frac{4}{5}}} + 5 t^{\frac{3}{2}} : \frac{1 + 25 t ^{\frac{23}{10}}}{5 t ^{\frac{4}{5}}}

= \frac{1 + 25 t ^{\frac{23}{10}}}{5 t ^{\frac{4}{5}}}

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Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[5]{t}+2sqrt(t^5) ?
The derivative of \sqrt[5]{t}+2sqrt(t^5) is (1+25t^{23/10})/(5t^{4/5)}
What is the first derivative of \sqrt[5]{t}+2sqrt(t^5) ?
The first derivative of \sqrt[5]{t}+2sqrt(t^5) is (1+25t^{23/10})/(5t^{4/5)}