What is the solution for (dy)/(dx)=e^{8x+y} ?

The solution for (dy)/(dx)=e^{8x+y} is y=-ln(-1/8 e^{8x}-c_{1})

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(dy)/(dx)=e^{8x+y}

\frac{d y}{d x} = e^{8 x + y}

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

Solution steps

\frac{d y}{d x} = e^{8 x + y}

Solve separable ODE:

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

y = - ln (- \frac{1}{8} e^{8 x} - c_{1})

f (x) = csc (x + 5)

\frac{d}{d x} (ln (\frac{5 x + 2}{5 x - 2}))

f (x) = \frac{1}{3 x + 1}

y^{^{'}} = t e^{- y}, y (0) = 1

\int_{0}^{1} cos (2 π x) d x

What is the solution for (dy)/(dx)=e^{8x+y} ?
The solution for (dy)/(dx)=e^{8x+y} is y=-ln(-1/8 e^{8x}-c_{1})